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11x^2-99=0
a = 11; b = 0; c = -99;
Δ = b2-4ac
Δ = 02-4·11·(-99)
Δ = 4356
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4356}=66$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-66}{2*11}=\frac{-66}{22} =-3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+66}{2*11}=\frac{66}{22} =3 $
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